String Concatenation and Operator Precedence
Ever wondered what the output of a seemingly straightforward piece of code might be, especially when it involves string concatenation and arithmetic operations? Consider the following C# examples:
Console.WriteLine("The value is: " + 11);
Console.WriteLine(3 + "º value");
Console.WriteLine("The value is: " + ( 3 + 1));
Console.WriteLine((3 + 18) + "º value");
Console.WriteLine("The value is: " + 2 + 4);
Console.WriteLine(5 + 6 + "º value");
This post aims not at debating best practices for string concatenation but at shedding light on operator precedence and its impact on our code's output.
When a string and a number are concatenated, the number is first converted to a string. Hence, the initial examples output:
The value is: 11
3º value
For operations requiring prior calculation before concatenation, parentheses alter the operation order, leading to outputs like:
The value is: 4
21º value
However, the outputs of the last two lines might not be as intuitive:
The value is: 24
11º value
Let's delve deeper. The curiosity arises, especially with the expected output of 56º value
for the last line, but instead, we get 11º value
. This discrepancy stems from the operations' order.
In the fifth example, starting with a string prompts immediate concatenation: The value is:
with 2
becomes The value is: 2
, followed by another concatenation with 4
, resulting in The value is: 24
.
Conversely, the sixth line starts with two numbers, leading to their addition (5 + 6 = 11)
, followed by concatenating this result with º value
, producing 11º value
.
Conclusion:
Understanding operator precedence is crucial to predicting code outcomes accurately. The + operator, when applied between strings and numbers, results in concatenation. A behavior not unique to C# but shared across many languages like JavaScript, Java and so on.